

fig.3 Next, we assign the astronaut Ï with the following problem: 4. The astronaut¢s experiments Astronaut Ï, in order o prove which of the two phases (Phase I or Phase II) his rocket is in, acts as follows: a. The device for measuring velocity To begin with, astronaut Ï places near the floor CD of his chamber, a device Å that radiates e.g. two parallel laser beams L_{1} and L_{2}. Those parallel laser beams are at a small distance d from one another, and are parallel to the floor CD of the chamber. Beams L_{1} and L_{2}
are connected to e.g. an oscilloscope, which acts as a chronometer.  
where t is the time recorded by the oscilloscope (chronometer), when mass m crossed the known distance d between the two parallel Laser beams L_{1} and L_{2}. b. Performing the experiments Astronaut Ï, after installing the device Å
for measuring velocity, as described above, now performs the following experiments:
Subsequently, conclusions Á and Â, as detailed above, are astronaut O¢s answer to the problem we set him. NOTE:
5. Various other conclusions drawn by the astronaut Astronaut O,
following the above correct answer he gave to the problem we set him, now proceeds to other conclusions regarding the Phase (Phase I or Phase II) his rocket S is in.
 
where F is the reading of dynamometer D and m is a known mass attached to the end of the dynamometer¢s spring.  
Thus, from the first of relations (2.6) the velocity õ_{1} of mass m_{1} , is:  
and the velocity õ_{2} of mass m_{2}, is:  
From relations (5) and (6), because m_{1}<m_{2}, it follows that õ_{1} > õ_{2}. Dividing now by member relations (5) and (6), we have: 
And based on relation (4), relation (7) yields:  
In relation (8), because m_{1}, m_{2}, k are known, astronaut Ï also knows the mass Ì of the celestial body, where his rocket S is docked. Also, from the first of relations (2.6), we have 

Now, by replacing the Ì in relation (9) with that of relation (8), we have: 
In relation (10) factors õ_{1}, h, m_{1}, k are known.  
We have:  
Where G is the constant of universal attraction.  
In relation (13) factors G, h, õ_{1}, m_{1}, m_{2}, k are known. Subsequently, on the basis of relation (13), astronaut Ï
also knows the radius R of mass Ì, where his rocket S is docked. 

In other words: ANOTHER MISTAKE BY EINSTEIN... As is well known, in the «equivalence principle» (weak equivalence principle), Einstein claims that: 
fig. 4 Now, if what Einstein claims above, fig. 4, on the «equivalence principle» were correct, then, during the elevator¢s free fall in the gravitational field of mass Ì, mass m_{2} would remain at the centre Ê
of the elevator chamber (as would be the case if the elevator were an inertial reference system S, away from gravitational fields).  
 
In other words:
Thus, in accordance wit the above, the «equivalence principle» of the General Theory of Relativity must be rejected as completely erroneous. A QUESTION ON THE «EQUIVALENCE PRINCIPLE»... It is well known that, in the «strong equivalence principle», Einstein accepts that: «All bodies (regardless of their mass) fall with the same velocity in the gravitational field of a mass M», (See http://www.tsolkas.gr/forums/777.jpg), book:Clifford M. Will, “Was Einstein right?”. RECAPITULATION Following all that we examined in our project, and on the basis on Conclusion I and Conclusion II, it is clearly and undoubtedly proven that the «equivalence principle» (weak and strong equivalence principle) is a completely
erroneous theory of Physics.  
© Copyright 2001 Tsolkas Christos. Web design by Wirenet Communications 