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Ether and
Magnetic field

Galileo and
Einstein
are wrong

Equivalence
Principle

Ether and
Equivalence
Principle

Proof  for
the advance
of Mercury's
perihelion


Open
Letter

 

The
Electro
gravitational
Theory I

The
Electro
gravitational
Theory II

The
Electro
gravitational
Theory III

The
Electro
gravitational
Theory IV

The
Electro
gravitational
Theory V

Generalised
Geometry

Mathematics
of degree

Video 01

Video 02


Ether
and
Light

 


Experiment 21
Experimental
Verification

 


Experiment 22
Experimental
Verification

 


The mistakes
of Einstein

 


Spherical
Shell
Problem
 

Recapitu-
lation


TECHNOLOGY
Fusion:
The “ZEUS”
machine

 


CERN/OPERA
IKARUS
TSOLKAS

 

THE EXPERIMENT GL

 THE EXPERIMENTAL APPARATUS (fig. 3)

D = platform (D).
= light source of wavelength .
L = light beam, from the light source .
Mo, M'o = flat mirrors (or prism T) for seperation of the light beam L in two light beams L1 and L2.
S1, S2 = closed tubes full water.
S3, S4 = closed tubes full benzol.
M1, M2, M3,M'1,M'2,M'3 = flat mirrors.
P = observer on platform (D).
P' = observer standing stationary onto the surface of Earth.
K0 = central light fringe.
 

THE EXPERIMENT. 

     The experiment GL, is executed as follows:

Phase I. The platform (D), is stationary relatively to an observer P' standing
               stationary, onto the surface of Earth.

     In this case, the light source , emits a light beam L, which then, falling onto the prism T, is divided in two light beams L1 and L2.
     The light beam L1 coming through the water of the tubes S1, S2 and the light beam L2 coming through the benzol of the tubes S3, S4 falling onto the mirrors M1, M2, M3 - M'1, M'2,M'3 respectively, are reflected.

     As a result, the above beams L1 and L2 interfere forming vertical rectilinear light and dark interference fringes, in the dioptre.
     During this phase of experiment, the vertical thread of the crossthread of dioptre is placed right on middle Ko of the central light fringe.

Phase II.  The platform (D), has uniform motion, with constant velocity ,
                 relatively to an observer P', standing stationary, onto the surface
                 of the Earth
.

     In this case, for the observer P, the total time t1 for the light, from light source to the middle Ko of central light fringe, through the tubes S1 and S2, will be:

   Where:

=

velocity of the light beam L1 into the water of the tube S1 for the observer P

=

velocity of the light beam L1 into the water of the tube S2 for the observer P

=

velocity of the light = 3108m/sec, in relation to the Earths frame of reference, namely in relation to the Earths etherosphere.

n1

=

 index of refraction of the water.

 

=

 velocity of the platform (D).

f1

=

Fizeau's drag coefficient, for the water.

     In the same way, for the observer P, total time t2 for the light, from light source to the middle Ko of central light fringe, through the tubes S3and S4, will be:

   Where:

=

velocity of the light beam L2 into the water of the tube S3 for the observer P

=

velocity of the light beam L2 into the water of the tube S4 for the observer P

n

=

 index of refraction of the benzol.

f2  

=

Fizeau's drag coefficient, for the benzol.

From the relations (1) and (2), we get:

where:

(4)        and

(5)

     The relation (3) means that, in this case (phase II), the observer P, will observe a shift of the interference fringes, which is equal to:

As it is Known, the Theory of Relativity, during the execution of the experiment GL, fig.3 accepts that:
In phase II of the experiment for the observer P the shift of the interference fringes, will always be =0 fringes.
But is this correct?

In my personal opinion, should the experiment be carried out, observer P will observe in phase II a shift of the interference fringes ≠0.

As a result, if during the execution of the experiment (phase II) the observer P should observe a shift of the interference fringes ≠0, then the whole philosophy and the entire axiomatic foundation of the Special Theory of Relativity is wrong.

EXAMPLE

Let us suppose our experiment is carried out given the following:

l = 1,00 m
l = 0,90 m
= 5,3 . 10-7m (monochromatic yellow light)
= 0,1 m/sec (velocity of the platform (D))
c = 3 . 108 m/sec
n1 = 1,33 (index of refraction of the water)
n2  = 1,50 (index of refraction of the benzol)

  (7)

From the relations (4) and (5), we have:

and

(8)

(9)

Substituting the above values (7), (8), and (9) in the relation (3), we get:

t  ≈ 1,333333 . 10-10  sec     (10)

and from the relation (6), we have a shift , which is equal to:

for the observer P.
Conwersely, according to the Theory of Relativity for the observer P the shift of the interference fringes, will always be =0 fringes.
Consequently, which is right, =0 fringes or =75.471 fringes?

In my personal view = 75.471 fringes is right and not =0 fringes.

NOTE: The letters G and L, are the initials of the English words “Greek Light”.

ATTENTION!

Should the experimental apparatus of the experiments by J.P. Cedarholm – C.H. Townes, Michelson – Morley, e.t.c. by placed on a moving vehicle (i.e. train, aircraft, satellite e.t.c.) then the existence of the etherosphere of the Earth will be immediately proven.
Unfortunately, this has never taken place to date.
Hence, this is the grave mistake of all Physicists who dealt with the existence of ether in nature.

©  Copyright 2001 Tsolkas Christos.  Web design by Wirenet Communications