| EXPERIMENT D.F.E.R.N. b Experiment D.F.E.R.N. b, which will be elaborated here below, is based on the same rationale as experiment D.F.E.R.N. Only that in experiment D.F.E.R.N. b, the gamma ray detector D is placed vertically relative to the linear orbit followed by the fast moving radioactive nuclei exiting accelerator A, Fig. 1(b). | |
| a. Therefore, according to the Theory of Relativity, detector D should measure a frequency í΄ of the gamma rays emitted by the radioactive nuclei which will be as follows: í΄ = í (1 – â2)1/2 / (1 – âcosè) (1) and because è = 900, namely, cosè = 0, relation (1) yields the following: í΄ = í (1–â2)1/2 (2)
b. However, in accordance with Classical Physics and based on the “New Ether Theory”, detector D should measure a gamma-ray frequency í΄΄ which will be as follows: í΄΄ = v (3) EXAMPLE Now, if õ/c = 0,8, as was the case in the previous example of experiment D.F.E.R.N., then according to the Theory of Relativity and based on relation (1), detector D shall measure the following frequency: í΄ = 0,6í (4) On the contrary, according to Classical Physics and to the “New Ether Theory” and on the basis of relation (3), detector D shall measure the following frequency: í΄΄ = v (5) where í is the frequency of the gamma rays emitted by the
radioactive nuclei when the latter are at rest (õ = 0).
Therefore, the question being raised as regards experiment D.F.E.R.N. b is the same as the one formulated in the previous experiment D.F.E.R.N., that is:
Which gamma-ray frequency will detector D measure in experiment D.F.E.R.N. b, í΄= 0,6í as the Theory of Relativity maintains or í΄΄ = v as the “New Ether Theory” holds?
Obviously, the answer to this question will be given only if experiment D.F.E.R.N. b, one of great significance to Physics, is carried out. Copyright 2006: Christos A. Tsolkas Christos Á. Tsolkas
January 17, 2006 |
